Solve for x 10=2-4(ax-3)

$10 = 2 - 4 (a x - 3)$

Rewrite the equation as $2 - 4 (a x - 3) = 10$ .

$2 - 4 (a x - 3) = 10$

Simplify $2 - 4 (a x - 3)$ .

Simplify each term.

Apply the distributive property.

$2 - 4 (a x) - 4 \cdot - 3 = 10$

Multiply $- 4$ by $- 3$ .

$2 - 4 a x + 12 = 10$

Add $2$ and $12$ .

$- 4 a x + 14 = 10$

Move all terms not containing $x$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$- 4 a x = 10 - 14$

Subtract $14$ from $10$ .

$- 4 a x = - 4$

Divide each term in $- 4 a x = - 4$ by $- 4 a$ and simplify.

Divide each term in $- 4 a x = - 4$ by $- 4 a$ .

$\frac{- 4 a x}{- 4 a} = \frac{- 4}{- 4 a}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 a x}{- 4 a} = \frac{- 4}{- 4 a}$

Rewrite the expression.

$\frac{a x}{a} = \frac{- 4}{- 4 a}$

Cancel the common factor of $a$ .

Cancel the common factor.

$\frac{a x}{a} = \frac{- 4}{- 4 a}$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 4 a}$

Simplify the right side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$x = \frac{- 4}{- 4 a}$

Rewrite the expression.

$x = \frac{1}{a}$