Solve for x (10+5x)/15=4

$\frac{10 + 5 x}{15} = 4$

Cancel the common factor of $10 + 5 x$ and $15$ .

Factor $5$ out of $10$ .

$\frac{5 \cdot 2 + 5 x}{15} = 4$

Factor $5$ out of $5 x$ .

$\frac{5 \cdot 2 + 5 (x)}{15} = 4$

Factor $5$ out of $5 \cdot 2 + 5 (x)$ .

$\frac{5 \cdot (2 + x)}{15} = 4$

Cancel the common factors.

Factor $5$ out of $15$ .

$\frac{5 \cdot (2 + x)}{5 (3)} = 4$

Cancel the common factor.

$\frac{5 \cdot (2 + x)}{5 \cdot 3} = 4$

Rewrite the expression.

$\frac{2 + x}{3} = 4$

$\frac{2 + x}{3} = 4$

$\frac{2 + x}{3} = 4$

Multiply both sides by $3$ .

$\frac{2 + x}{3} \cdot 3 = 4 \cdot 3$

Simplify.

Simplify the left side.

Simplify $\frac{2 + x}{3} \cdot 3$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{2 + x}{3} \cdot 3 = 4 \cdot 3$

Rewrite the expression.

$2 + x = 4 \cdot 3$

$2 + x = 4 \cdot 3$

Reorder $2$ and $x$ .

$x + 2 = 4 \cdot 3$

$x + 2 = 4 \cdot 3$

$x + 2 = 4 \cdot 3$

Simplify the right side.

Multiply $4$ by $3$ .

$x + 2 = 12$

$x + 2 = 12$

$x + 2 = 12$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = 12 - 2$

Subtract $2$ from $12$ .

$x = 10$

$x = 10$

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