Solve for x -10(x-1)=10-10x

$- 10 (x - 1) = 10 - 10 x$

Step 1

Simplify $- 10 (x - 1)$ .

Rewrite.

$0 + 0 - 10 (x - 1) = 10 - 10 x$

Simplify by adding zeros.

$- 10 (x - 1) = 10 - 10 x$

Apply the distributive property.

$- 10 x - 10 \cdot - 1 = 10 - 10 x$

Multiply $- 10$ by $- 1$ .

$- 10 x + 10 = 10 - 10 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$- 10 x + 10 + 10 x = 10$

Combine the opposite terms in $- 10 x + 10 + 10 x$ .

Add $- 10 x$ and $10 x$ .

$0 + 10 = 10$

Add $0$ and $10$ .

$10 = 10$

Step 3

Since $10 = 10$ , the equation will always be true for any value of $x$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$