Solve for x 10^x=35

$10^{x} = 35$

Step 1

Take the base $10$ logarithm of both sides of the equation to remove the variable from the exponent.

$\log (10^{x}) = \log (35)$

Step 2

Expand the left side.

Expand $\log (10^{x})$ by moving $x$ outside the logarithm.

$x \log (10) = \log (35)$

Logarithm base $10$ of $10$ is $1$ .

$x \cdot 1 = \log (35)$

Multiply $x$ by $1$ .

$x = \log (35)$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = \log (35)$

Decimal Form:

$x = 1.54406804 \dots$