Solve for x 10+x=5(1/5x+2)

$10 + x = 5 (\frac{1}{5} x + 2)$

Simplify $5 (\frac{1}{5} x + 2)$ .

Rewrite.

$10 + x = 0 + 0 + 5 (\frac{1}{5} x + 2)$

Simplify by adding zeros.

$10 + x = 5 (\frac{1}{5} x + 2)$

Combine $\frac{1}{5}$ and $x$ .

$10 + x = 5 (\frac{x}{5} + 2)$

Apply the distributive property.

$10 + x = 5 \frac{x}{5} + 5 \cdot 2$

Cancel the common factor of $5$ .

Cancel the common factor.

$10 + x = 5 \frac{x}{5} + 5 \cdot 2$

Rewrite the expression.

$10 + x = x + 5 \cdot 2$

Multiply $5$ by $2$ .

$10 + x = x + 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$10 + x - x = 10$

Combine the opposite terms in $10 + x - x$ .

Subtract $x$ from $x$ .

$10 + 0 = 10$

Add $10$ and $0$ .

$10 = 10$

Since $10 = 10$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$