Solve for x (10x+3)=(3x-4)

$(10 x + 3) = (3 x - 4)$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$10 x + 3 - 3 x = - 4$

Subtract $3 x$ from $10 x$ .

$7 x + 3 = - 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$7 x = - 4 - 3$

Subtract $3$ from $- 4$ .

$7 x = - 7$

Divide each term in $7 x = - 7$ by $7$ and simplify.

Divide each term in $7 x = - 7$ by $7$ .

$\frac{7 x}{7} = \frac{- 7}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{- 7}{7}$

Divide $x$ by $1$ .

$x = \frac{- 7}{7}$

Simplify the right side.

Divide $- 7$ by $7$ .

$x = - 1$