Solve for x 10x-3(x-6)=x+30

$10 x - 3 (x - 6) = x + 30$

Step 1

Simplify $10 x - 3 (x - 6)$ .

Simplify each term.

Apply the distributive property.

$10 x - 3 x - 3 \cdot - 6 = x + 30$

Multiply $- 3$ by $- 6$ .

$10 x - 3 x + 18 = x + 30$

Subtract $3 x$ from $10 x$ .

$7 x + 18 = x + 30$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$7 x + 18 - x = 30$

Subtract $x$ from $7 x$ .

$6 x + 18 = 30$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $18$ from both sides of the equation.

$6 x = 30 - 18$

Subtract $18$ from $30$ .

$6 x = 12$

Step 4

Divide each term in $6 x = 12$ by $6$ and simplify.

Divide each term in $6 x = 12$ by $6$ .

$\frac{6 x}{6} = \frac{12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{12}{6}$

Divide $x$ by $1$ .

$x = \frac{12}{6}$

Simplify the right side.

Divide $12$ by $6$ .

$x = 2$