Solve for x 11+2x=3+4x-3x

$11 + 2 x = 3 + 4 x - 3 x$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 + 4 x - 3 x = 11 + 2 x$

Step 2

Subtract $3 x$ from $4 x$ .

$3 + x = 11 + 2 x$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$3 + x - 2 x = 11$

Subtract $2 x$ from $x$ .

$3 - x = 11$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- x = 11 - 3$

Subtract $3$ from $11$ .

$- x = 8$

Step 5

Divide each term in $- x = 8$ by $- 1$ and simplify.

Divide each term in $- x = 8$ by $- 1$ .

$\frac{- x}{- 1} = \frac{8}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{8}{- 1}$

Divide $x$ by $1$ .

$x = \frac{8}{- 1}$

Simplify the right side.

Divide $8$ by $- 1$ .

$x = - 8$