Solve for x 11kx+13kx=6 for x

$11 k x + 13 k x = 6$ for $x$

Add $11 k x$ and $13 k x$ .

$24 k x = 6$

Divide each term in $24 k x = 6$ by $24 k$ and simplify.

Divide each term in $24 k x = 6$ by $24 k$ .

$\frac{24 k x}{24 k} = \frac{6}{24 k}$

Simplify the left side.

Cancel the common factor of $24$ .

Cancel the common factor.

$\frac{24 k x}{24 k} = \frac{6}{24 k}$

Rewrite the expression.

$\frac{k x}{k} = \frac{6}{24 k}$

Cancel the common factor of $k$ .

Cancel the common factor.

$\frac{k x}{k} = \frac{6}{24 k}$

Divide $x$ by $1$ .

$x = \frac{6}{24 k}$

Simplify the right side.

Cancel the common factor of $6$ and $24$ .

Factor $6$ out of $6$ .

$x = \frac{6 (1)}{24 k}$

Cancel the common factors.

Factor $6$ out of $24 k$ .

$x = \frac{6 (1)}{6 (4 k)}$

Cancel the common factor.

$x = \frac{6 \cdot 1}{6 (4 k)}$

Rewrite the expression.

$x = \frac{1}{4 k}$