Solve for x 11x+1=-1+x

$11 x + 1 = - 1 + x$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$11 x + 1 - x = - 1$

Subtract $x$ from $11 x$ .

$10 x + 1 = - 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$10 x = - 1 - 1$

Subtract $1$ from $- 1$ .

$10 x = - 2$

Divide each term in $10 x = - 2$ by $10$ and simplify.

Divide each term in $10 x = - 2$ by $10$ .

$\frac{10 x}{10} = \frac{- 2}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 x}{10} = \frac{- 2}{10}$

Divide $x$ by $1$ .

$x = \frac{- 2}{10}$

Simplify the right side.

Cancel the common factor of $- 2$ and $10$ .

Factor $2$ out of $- 2$ .

$x = \frac{2 (- 1)}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$x = \frac{2 \cdot - 1}{2 \cdot 5}$

Cancel the common factor.

$x = \frac{2 \cdot - 1}{2 \cdot 5}$

Rewrite the expression.

$x = \frac{- 1}{5}$

Move the negative in front of the fraction.

$x = - \frac{1}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{5}$

Decimal Form:

$x = - 0.2$