Solve for x 11x+3=4x^2

$11 x + 3 = 4 x^{2}$

Step 1

Subtract $4 x^{2}$ from both sides of the equation.

$11 x + 3 - 4 x^{2} = 0$

Step 2

Factor the left side of the equation.

Factor $- 1$ out of $11 x + 3 - 4 x^{2}$ .

Reorder the expression.

Move $3$ .

$11 x - 4 x^{2} + 3 = 0$

Reorder $11 x$ and $- 4 x^{2}$ .

$- 4 x^{2} + 11 x + 3 = 0$

Factor $- 1$ out of $- 4 x^{2}$ .

$- (4 x^{2}) + 11 x + 3 = 0$

Factor $- 1$ out of $11 x$ .

$- (4 x^{2}) - (- 11 x) + 3 = 0$

Rewrite $3$ as $- 1 (- 3)$ .

$- (4 x^{2}) - (- 11 x) - 1 \cdot - 3 = 0$

Factor $- 1$ out of $- (4 x^{2}) - (- 11 x)$ .

$- (4 x^{2} - 11 x) - 1 \cdot - 3 = 0$

Factor $- 1$ out of $- (4 x^{2} - 11 x) - 1 (- 3)$ .

$- (4 x^{2} - 11 x - 3) = 0$

Factor.

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 4 \cdot - 3 = - 12$ and whose sum is $b = - 11$ .

Factor $- 11$ out of $- 11 x$ .

$- (4 x^{2} - 11 x - 3) = 0$

Rewrite $- 11$ as $1$ plus $- 12$

$- (4 x^{2} + (1 - 12) x - 3) = 0$

Apply the distributive property.

$- (4 x^{2} + 1 x - 12 x - 3) = 0$

Multiply $x$ by $1$ .

$- (4 x^{2} + x - 12 x - 3) = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$- ((4 x^{2} + x) - 12 x - 3) = 0$

Factor out the greatest common factor (GCF) from each group.

$- (x (4 x + 1) - 3 (4 x + 1)) = 0$

Factor the polynomial by factoring out the greatest common factor, $4 x + 1$ .

$- ((4 x + 1) (x - 3)) = 0$

Remove unnecessary parentheses.

$- (4 x + 1) (x - 3) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$4 x + 1 = 0$

$x - 3 = 0$

Step 4

Set $4 x + 1$ equal to $0$ and solve for $x$ .

Set $4 x + 1$ equal to $0$ .

$4 x + 1 = 0$

Solve $4 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$4 x = - 1$

Divide each term in $4 x = - 1$ by $4$ and simplify.

Divide each term in $4 x = - 1$ by $4$ .

$\frac{4 x}{4} = \frac{- 1}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 1}{4}$

Divide $x$ by $1$ .

$x = \frac{- 1}{4}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{4}$

Step 5

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Step 6

The final solution is all the values that make $- (4 x + 1) (x - 3) = 0$ true.

$x = - \frac{1}{4}, 3$

Step 7

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{4}, 3$

Decimal Form:

$x = - 0.25, 3$

Solve for x 11x+3=4x^2

Related Questions

Support LCMGCF.com by disabling your adblocker.