Solve for x 12-((2x)/3+x)=2

$12 - (\frac{2 x}{3} + x) = 2$

Step 1

Simplify each term.

To write $x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$12 - (\frac{2 x}{3} + x \cdot \frac{3}{3}) = 2$

Combine $x$ and $\frac{3}{3}$ .

$12 - (\frac{2 x}{3} + \frac{x \cdot 3}{3}) = 2$

Combine the numerators over the common denominator.

$12 - \frac{2 x + x \cdot 3}{3} = 2$

Simplify the numerator.

Move $3$ to the left of $x$ .

$12 - \frac{2 x + 3 \cdot x}{3} = 2$

Add $2 x$ and $3 x$ .

$12 - \frac{5 x}{3} = 2$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- \frac{5 x}{3} = 2 - 12$

Subtract $12$ from $2$ .

$- \frac{5 x}{3} = - 10$

Step 3

Multiply both sides of the equation by $- \frac{3}{5}$ .

$- \frac{3}{5} (- \frac{5 x}{3}) = - \frac{3}{5} \cdot - 10$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{5} (- \frac{5 x}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{5}$ into the numerator.

$\frac{- 3}{5} (- \frac{5 x}{3}) = - \frac{3}{5} \cdot - 10$

Move the leading negative in $- \frac{5 x}{3}$ into the numerator.

$\frac{- 3}{5} \cdot \frac{- 5 x}{3} = - \frac{3}{5} \cdot - 10$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{5} \cdot \frac{- 5 x}{3} = - \frac{3}{5} \cdot - 10$

Cancel the common factor.

$\frac{3 \cdot - 1}{5} \cdot \frac{- 5 x}{3} = - \frac{3}{5} \cdot - 10$

Rewrite the expression.

$\frac{- 1}{5} (- 5 x) = - \frac{3}{5} \cdot - 10$

Cancel the common factor of $5$ .

Factor $5$ out of $- 5 x$ .

$\frac{- 1}{5} (5 (- x)) = - \frac{3}{5} \cdot - 10$

Cancel the common factor.

$\frac{- 1}{5} (5 (- x)) = - \frac{3}{5} \cdot - 10$

Rewrite the expression.

$- - x = - \frac{3}{5} \cdot - 10$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{3}{5} \cdot - 10$

Multiply $x$ by $1$ .

$x = - \frac{3}{5} \cdot - 10$

Simplify the right side.

Simplify $- \frac{3}{5} \cdot - 10$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{3}{5}$ into the numerator.

$x = \frac{- 3}{5} \cdot - 10$

Factor $5$ out of $- 10$ .

$x = \frac{- 3}{5} \cdot (5 (- 2))$

Cancel the common factor.

$x = \frac{- 3}{5} \cdot (5 \cdot - 2)$

Rewrite the expression.

$x = - 3 \cdot - 2$

Multiply $- 3$ by $- 2$ .

$x = 6$

Solve for x 12-((2x)/3+x)=2

Related Questions

Support LCMGCF.com by disabling your adblocker.