Solve for x 12-3x+4x=9+10x+8

$12 - 3 x + 4 x = 9 + 10 x + 8$

Add $- 3 x$ and $4 x$ .

$12 + x = 9 + 10 x + 8$

Add $9$ and $8$ .

$12 + x = 10 x + 17$

Move all terms containing $x$ to the left side of the equation.

Subtract $10 x$ from both sides of the equation.

$12 + x - 10 x = 17$

Subtract $10 x$ from $x$ .

$12 - 9 x = 17$

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- 9 x = 17 - 12$

Subtract $12$ from $17$ .

$- 9 x = 5$

Divide each term in $- 9 x = 5$ by $- 9$ and simplify.

Divide each term in $- 9 x = 5$ by $- 9$ .

$\frac{- 9 x}{- 9} = \frac{5}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 x}{- 9} = \frac{5}{- 9}$

Divide $x$ by $1$ .

$x = \frac{5}{- 9}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{5}{9}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{5}{9}$

Decimal Form:

$x = - 0.\overline{5}$