Solve for x 12=-4(-6x-3)

$12 = - 4 (- 6 x - 3)$

Step 1

Rewrite the equation as $- 4 (- 6 x - 3) = 12$ .

$- 4 (- 6 x - 3) = 12$

Step 2

Divide each term in $- 4 (- 6 x - 3) = 12$ by $- 4$ and simplify.

Divide each term in $- 4 (- 6 x - 3) = 12$ by $- 4$ .

$\frac{- 4 (- 6 x - 3)}{- 4} = \frac{12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 (- 6 x - 3)}{- 4} = \frac{12}{- 4}$

Divide $- 6 x - 3$ by $1$ .

$- 6 x - 3 = \frac{12}{- 4}$

Simplify the right side.

Divide $12$ by $- 4$ .

$- 6 x - 3 = - 3$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- 6 x = - 3 + 3$

Add $- 3$ and $3$ .

$- 6 x = 0$

Step 4

Divide each term in $- 6 x = 0$ by $- 6$ and simplify.

Divide each term in $- 6 x = 0$ by $- 6$ .

$\frac{- 6 x}{- 6} = \frac{0}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} = \frac{0}{- 6}$

Divide $x$ by $1$ .

$x = \frac{0}{- 6}$

Simplify the right side.

Divide $0$ by $- 6$ .

$x = 0$