Solve for x (12+6x)/3=(5-9)/2

$\frac{12 + 6 x}{3} = \frac{5 - 9}{2}$

Step 1

Cancel the common factor of $12 + 6 x$ and $3$ .

Factor $3$ out of $12$ .

$\frac{3 \cdot 4 + 6 x}{3} = \frac{5 - 9}{2}$

Factor $3$ out of $6 x$ .

$\frac{3 \cdot 4 + 3 (2 x)}{3} = \frac{5 - 9}{2}$

Factor $3$ out of $3 (4) + 3 (2 x)$ .

$\frac{3 (4 + 2 x)}{3} = \frac{5 - 9}{2}$

Cancel the common factors.

Factor $3$ out of $3$ .

$\frac{3 (4 + 2 x)}{3 (1)} = \frac{5 - 9}{2}$

Cancel the common factor.

$\frac{3 (4 + 2 x)}{3 \cdot 1} = \frac{5 - 9}{2}$

Rewrite the expression.

$\frac{4 + 2 x}{1} = \frac{5 - 9}{2}$

Divide $4 + 2 x$ by $1$ .

$4 + 2 x = \frac{5 - 9}{2}$

Step 2

Solve for $x$ .

Simplify $\frac{5 - 9}{2}$ .

Subtract $9$ from $5$ .

$4 + 2 x = \frac{- 4}{2}$

Divide $- 4$ by $2$ .

$4 + 2 x = - 2$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$2 x = - 2 - 4$

Subtract $4$ from $- 2$ .

$2 x = - 6$

Divide each term in $2 x = - 6$ by $2$ and simplify.

Divide each term in $2 x = - 6$ by $2$ .

$\frac{2 x}{2} = \frac{- 6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 6}{2}$

Divide $x$ by $1$ .

$x = \frac{- 6}{2}$

Simplify the right side.

Divide $- 6$ by $2$ .

$x = - 3$