Solve for x 13-4x=1-x

$13 - 4 x = 1 - x$

Step 1

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$13 - 4 x + x = 1$

Add $- 4 x$ and $x$ .

$13 - 3 x = 1$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 3 x = 1 - 13$

Subtract $13$ from $1$ .

$- 3 x = - 12$

Step 3

Divide each term in $- 3 x = - 12$ by $- 3$ and simplify.

Divide each term in $- 3 x = - 12$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 12}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 12}{- 3}$

Divide $x$ by $1$ .

$x = \frac{- 12}{- 3}$

Simplify the right side.

Divide $- 12$ by $- 3$ .

$x = 4$