Solve for x 13(x-3)=39

$13 (x - 3) = 39$

Step 1

Divide each term in $13 (x - 3) = 39$ by $13$ and simplify.

Divide each term in $13 (x - 3) = 39$ by $13$ .

$\frac{13 (x - 3)}{13} = \frac{39}{13}$

Simplify the left side.

Cancel the common factor of $13$ .

Cancel the common factor.

$\frac{13 (x - 3)}{13} = \frac{39}{13}$

Divide $x - 3$ by $1$ .

$x - 3 = \frac{39}{13}$

Simplify the right side.

Divide $39$ by $13$ .

$x - 3 = 3$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$x = 3 + 3$

Add $3$ and $3$ .

$x = 6$