Solve for x (13k+10x)+(-8x-9k)=12k

$(13 k + 10 x) + (- 8 x - 9 k) = 12 k$

Simplify $13 k + 10 x - 8 x - 9 k$ .

Subtract $9 k$ from $13 k$ .

$4 k + 10 x - 8 x = 12 k$

Subtract $8 x$ from $10 x$ .

$4 k + 2 x = 12 k$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4 k$ from both sides of the equation.

$2 x = 12 k - 4 k$

Subtract $4 k$ from $12 k$ .

$2 x = 8 k$

Divide each term in $2 x = 8 k$ by $2$ and simplify.

Divide each term in $2 x = 8 k$ by $2$ .

$\frac{2 x}{2} = \frac{8 k}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{8 k}{2}$

Divide $x$ by $1$ .

$x = \frac{8 k}{2}$

Simplify the right side.

Cancel the common factor of $8$ and $2$ .

Factor $2$ out of $8 k$ .

$x = \frac{2 (4 k)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$x = \frac{2 (4 k)}{2 (1)}$

Cancel the common factor.

$x = \frac{2 (4 k)}{2 \cdot 1}$

Rewrite the expression.

$x = \frac{4 k}{1}$

Divide $4 k$ by $1$ .

$x = 4 k$