Solve for x 14+56x-22=8(7x-1)

$14 + 56 x - 22 = 8 (7 x - 1)$

Subtract $22$ from $14$ .

$56 x - 8 = 8 (7 x - 1)$

Simplify $8 (7 x - 1)$ .

Apply the distributive property.

$56 x - 8 = 8 (7 x) + 8 \cdot - 1$

Multiply.

Multiply $7$ by $8$ .

$56 x - 8 = 56 x + 8 \cdot - 1$

Multiply $8$ by $- 1$ .

$56 x - 8 = 56 x - 8$

Move all terms containing $x$ to the left side of the equation.

Subtract $56 x$ from both sides of the equation.

$56 x - 8 - 56 x = - 8$

Combine the opposite terms in $56 x - 8 - 56 x$ .

Subtract $56 x$ from $56 x$ .

$0 - 8 = - 8$

Subtract $8$ from $0$ .

$- 8 = - 8$

Since $- 8 = - 8$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$