Solve for x 15=5/3(x+12)

$15 = \frac{5}{3} (x + 12)$

Step 1

Rewrite the equation as $\frac{5}{3} \cdot (x + 12) = 15$ .

$\frac{5}{3} \cdot (x + 12) = 15$

Step 2

Multiply both sides of the equation by $\frac{3}{5}$ .

$\frac{3}{5} (\frac{5}{3} \cdot (x + 12)) = \frac{3}{5} \cdot 15$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{5} (\frac{5}{3} \cdot (x + 12))$ .

Apply the distributive property.

$\frac{3}{5} (\frac{5}{3} x + \frac{5}{3} \cdot 12) = \frac{3}{5} \cdot 15$

Combine $\frac{5}{3}$ and $x$ .

$\frac{3}{5} (\frac{5 x}{3} + \frac{5}{3} \cdot 12) = \frac{3}{5} \cdot 15$

Cancel the common factor of $3$ .

Factor $3$ out of $12$ .

$\frac{3}{5} (\frac{5 x}{3} + \frac{5}{3} \cdot (3 (4))) = \frac{3}{5} \cdot 15$

Cancel the common factor.

$\frac{3}{5} (\frac{5 x}{3} + \frac{5}{3} \cdot (3 \cdot 4)) = \frac{3}{5} \cdot 15$

Rewrite the expression.

$\frac{3}{5} (\frac{5 x}{3} + 5 \cdot 4) = \frac{3}{5} \cdot 15$

Multiply $5$ by $4$ .

$\frac{3}{5} (\frac{5 x}{3} + 20) = \frac{3}{5} \cdot 15$

Apply the distributive property.

$\frac{3}{5} \cdot \frac{5 x}{3} + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{5} \cdot \frac{5 x}{3} + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Rewrite the expression.

$\frac{1}{5} (5 x) + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Cancel the common factor of $5$ .

Factor $5$ out of $5 x$ .

$\frac{1}{5} (5 (x)) + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Cancel the common factor.

$\frac{1}{5} (5 x) + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Rewrite the expression.

$x + \frac{3}{5} \cdot 20 = \frac{3}{5} \cdot 15$

Cancel the common factor of $5$ .

Factor $5$ out of $20$ .

$x + \frac{3}{5} \cdot (5 (4)) = \frac{3}{5} \cdot 15$

Cancel the common factor.

$x + \frac{3}{5} \cdot (5 \cdot 4) = \frac{3}{5} \cdot 15$

Rewrite the expression.

$x + 3 \cdot 4 = \frac{3}{5} \cdot 15$

Multiply $3$ by $4$ .

$x + 12 = \frac{3}{5} \cdot 15$

Simplify the right side.

Simplify $\frac{3}{5} \cdot 15$ .

Cancel the common factor of $5$ .

Factor $5$ out of $15$ .

$x + 12 = \frac{3}{5} \cdot (5 (3))$

Cancel the common factor.

$x + 12 = \frac{3}{5} \cdot (5 \cdot 3)$

Rewrite the expression.

$x + 12 = 3 \cdot 3$

Multiply $3$ by $3$ .

$x + 12 = 9$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$x = 9 - 12$

Subtract $12$ from $9$ .

$x = - 3$

Solve for x 15=5/3(x+12)

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