Solve for x 16+7x-5+x=11x-3-2x

$16 + 7 x - 5 + x = 11 x - 3 - 2 x$

Simplify $16 + 7 x - 5 + x$ .

Subtract $5$ from $16$ .

$7 x + 11 + x = 11 x - 3 - 2 x$

Add $7 x$ and $x$ .

$8 x + 11 = 11 x - 3 - 2 x$

Subtract $2 x$ from $11 x$ .

$8 x + 11 = 9 x - 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$8 x + 11 - 9 x = - 3$

Subtract $9 x$ from $8 x$ .

$- x + 11 = - 3$

Move all terms not containing $x$ to the right side of the equation.

Subtract $11$ from both sides of the equation.

$- x = - 3 - 11$

Subtract $11$ from $- 3$ .

$- x = - 14$

Divide each term in $- x = - 14$ by $- 1$ and simplify.

Divide each term in $- x = - 14$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 14}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 14}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 14}{- 1}$

Simplify the right side.

Divide $- 14$ by $- 1$ .

$x = 14$