Solve for x -18-6x=6(1+3x)

$- 18 - 6 x = 6 (1 + 3 x)$

Step 1

Simplify $6 (1 + 3 x)$ .

Rewrite.

$- 18 - 6 x = 0 + 0 + 6 (1 + 3 x)$

Simplify by adding zeros.

$- 18 - 6 x = 6 (1 + 3 x)$

Apply the distributive property.

$- 18 - 6 x = 6 \cdot 1 + 6 (3 x)$

Multiply.

Multiply $6$ by $1$ .

$- 18 - 6 x = 6 + 6 (3 x)$

Multiply $3$ by $6$ .

$- 18 - 6 x = 6 + 18 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $18 x$ from both sides of the equation.

$- 18 - 6 x - 18 x = 6$

Subtract $18 x$ from $- 6 x$ .

$- 18 - 24 x = 6$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $18$ to both sides of the equation.

$- 24 x = 6 + 18$

Add $6$ and $18$ .

$- 24 x = 24$

Step 4

Divide each term in $- 24 x = 24$ by $- 24$ and simplify.

Divide each term in $- 24 x = 24$ by $- 24$ .

$\frac{- 24 x}{- 24} = \frac{24}{- 24}$

Simplify the left side.

Cancel the common factor of $- 24$ .

Cancel the common factor.

$\frac{- 24 x}{- 24} = \frac{24}{- 24}$

Divide $x$ by $1$ .

$x = \frac{24}{- 24}$

Simplify the right side.

Divide $24$ by $- 24$ .

$x = - 1$