Solve for x 19x+1<x+37

$19 x + 1 < x + 37$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $x$ from both sides of the inequality.

$19 x + 1 - x < 37$

Subtract $x$ from $19 x$ .

$18 x + 1 < 37$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$18 x < 37 - 1$

Subtract $1$ from $37$ .

$18 x < 36$

Step 3

Divide each term in $18 x < 36$ by $18$ and simplify.

Divide each term in $18 x < 36$ by $18$ .

$\frac{18 x}{18} < \frac{36}{18}$

Simplify the left side.

Cancel the common factor of $18$ .

Cancel the common factor.

$\frac{18 x}{18} < \frac{36}{18}$

Divide $x$ by $1$ .

$x < \frac{36}{18}$

Simplify the right side.

Divide $36$ by $18$ .

$x < 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < 2$

Interval Notation:

$(- \infty, 2)$