Solve for x 2=(1/2)^x

$2 = {(\frac{1}{2})}^{x}$

Rewrite the equation as ${(\frac{1}{2})}^{x} = 2$ .

${(\frac{1}{2})}^{x} = 2$

Apply the product rule to $\frac{1}{2}$ .

$\frac{1^{x}}{2^{x}} = 2$

One to any power is one.

$\frac{1}{2^{x}} = 2$

Move $2^{x}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$2^{- x} = 2$

Create equivalent expressions in the equation that all have equal bases.

$2^{- x} = 2^{1}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$- x = 1$

Divide each term in $- x = 1$ by $- 1$ and simplify.

Divide each term in $- x = 1$ by $- 1$ .

$\frac{- x}{- 1} = \frac{1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{1}{- 1}$

Divide $x$ by $1$ .

$x = \frac{1}{- 1}$

Simplify the right side.

Divide $1$ by $- 1$ .

$x = - 1$