Solve for x 2(1-3(x+2))=-x

$2 (1 - 3 (x + 2)) = - x$

Step 1

Simplify $2 (1 - 3 (x + 2))$ .

Start simplifying.

$0 + 0 + 2 (1 - 3 (x + 2)) = - x$

Simplify by adding zeros.

$2 (1 - 3 (x + 2)) = - x$

Simplify each term.

Apply the distributive property.

$2 (1 - 3 x - 3 \cdot 2) = - x$

Multiply $- 3$ by $2$ .

$2 (1 - 3 x - 6) = - x$

Simplify by multiplying through.

Subtract $6$ from $1$ .

$2 (- 3 x - 5) = - x$

Apply the distributive property.

$2 (- 3 x) + 2 \cdot - 5 = - x$

Multiply.

Multiply $- 3$ by $2$ .

$- 6 x + 2 \cdot - 5 = - x$

Multiply $2$ by $- 5$ .

$- 6 x - 10 = - x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$- 6 x - 10 + x = 0$

Add $- 6 x$ and $x$ .

$- 5 x - 10 = 0$

Step 3

Add $10$ to both sides of the equation.

$- 5 x = 10$

Step 4

Divide each term in $- 5 x = 10$ by $- 5$ and simplify.

Divide each term in $- 5 x = 10$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{10}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{10}{- 5}$

Divide $x$ by $1$ .

$x = \frac{10}{- 5}$

Simplify the right side.

Divide $10$ by $- 5$ .

$x = - 2$