Solve for x 2(-2x+2)-3x+3=0

$2 (- 2 x + 2) - 3 x + 3 = 0$

Step 1

Simplify $2 (- 2 x + 2) - 3 x + 3$ .

Simplify each term.

Apply the distributive property.

$2 (- 2 x) + 2 \cdot 2 - 3 x + 3 = 0$

Multiply $- 2$ by $2$ .

$- 4 x + 2 \cdot 2 - 3 x + 3 = 0$

Multiply $2$ by $2$ .

$- 4 x + 4 - 3 x + 3 = 0$

Simplify by adding terms.

Subtract $3 x$ from $- 4 x$ .

$- 7 x + 4 + 3 = 0$

Add $4$ and $3$ .

$- 7 x + 7 = 0$

Step 2

Subtract $7$ from both sides of the equation.

$- 7 x = - 7$

Step 3

Divide each term in $- 7 x = - 7$ by $- 7$ and simplify.

Divide each term in $- 7 x = - 7$ by $- 7$ .

$\frac{- 7 x}{- 7} = \frac{- 7}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 x}{- 7} = \frac{- 7}{- 7}$

Divide $x$ by $1$ .

$x = \frac{- 7}{- 7}$

Simplify the right side.

Divide $- 7$ by $- 7$ .

$x = 1$