Solve for x 2/3(1/2x+12)=1/2(1/3x+14)-3 ?

$\frac{2}{3} (\frac{1}{2} x + 12) = \frac{1}{2} (\frac{1}{3} x + 14) - 3$ ?

Simplify $\frac{2}{3} \cdot (\frac{1}{2} x + 12)$ .

Rewrite.

$0 + 0 + \frac{2}{3} \cdot (\frac{1}{2} x + 12) = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Simplify by adding zeros.

$\frac{2}{3} \cdot (\frac{1}{2} x + 12) = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Combine $\frac{1}{2}$ and $x$ .

$\frac{2}{3} \cdot (\frac{x}{2} + 12) = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Apply the distributive property.

$\frac{2}{3} \cdot \frac{x}{2} + \frac{2}{3} \cdot 12 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{3} \cdot \frac{x}{2} + \frac{2}{3} \cdot 12 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Rewrite the expression.

$\frac{1}{3} x + \frac{2}{3} \cdot 12 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Combine $\frac{1}{3}$ and $x$ .

$\frac{x}{3} + \frac{2}{3} \cdot 12 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Cancel the common factor of $3$ .

Factor $3$ out of $12$ .

$\frac{x}{3} + \frac{2}{3} \cdot (3 (4)) = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Cancel the common factor.

$\frac{x}{3} + \frac{2}{3} \cdot (3 \cdot 4) = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Rewrite the expression.

$\frac{x}{3} + 2 \cdot 4 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Multiply $2$ by $4$ .

$\frac{x}{3} + 8 = \frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$

Simplify $\frac{1}{2} \cdot (\frac{1}{3} x + 14) - 3$ .

Simplify each term.

Combine $\frac{1}{3}$ and $x$ .

$\frac{x}{3} + 8 = \frac{1}{2} \cdot (\frac{x}{3} + 14) - 3$

Apply the distributive property.

$\frac{x}{3} + 8 = \frac{1}{2} \cdot \frac{x}{3} + \frac{1}{2} \cdot 14 - 3$

Multiply $\frac{1}{2} \cdot \frac{x}{3}$ .

Multiply $\frac{1}{2}$ by $\frac{x}{3}$ .

$\frac{x}{3} + 8 = \frac{x}{2 \cdot 3} + \frac{1}{2} \cdot 14 - 3$

Multiply $2$ by $3$ .

$\frac{x}{3} + 8 = \frac{x}{6} + \frac{1}{2} \cdot 14 - 3$

Cancel the common factor of $2$ .

Factor $2$ out of $14$ .

$\frac{x}{3} + 8 = \frac{x}{6} + \frac{1}{2} \cdot (2 (7)) - 3$

Cancel the common factor.

$\frac{x}{3} + 8 = \frac{x}{6} + \frac{1}{2} \cdot (2 \cdot 7) - 3$

Rewrite the expression.

$\frac{x}{3} + 8 = \frac{x}{6} + 7 - 3$

Subtract $3$ from $7$ .

$\frac{x}{3} + 8 = \frac{x}{6} + 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $\frac{x}{6}$ from both sides of the equation.

$\frac{x}{3} + 8 - \frac{x}{6} = 4$

To write $\frac{x}{3}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x}{3} \cdot \frac{2}{2} - \frac{x}{6} + 8 = 4$

Write each expression with a common denominator of $6$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{x}{3}$ by $\frac{2}{2}$ .

$\frac{x \cdot 2}{3 \cdot 2} - \frac{x}{6} + 8 = 4$

Multiply $3$ by $2$ .

$\frac{x \cdot 2}{6} - \frac{x}{6} + 8 = 4$

Combine the numerators over the common denominator.

$\frac{x \cdot 2 - x}{6} + 8 = 4$

Subtract $x$ from $x \cdot 2$ .

Reorder $x$ and $2$ .

$\frac{2 \cdot x - x}{6} + 8 = 4$

Subtract $x$ from $2 \cdot x$ .

$\frac{x}{6} + 8 = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$\frac{x}{6} = 4 - 8$

Subtract $8$ from $4$ .

$\frac{x}{6} = - 4$

Multiply both sides of the equation by $6$ .

$6 \frac{x}{6} = 6 \cdot - 4$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$6 \frac{x}{6} = 6 \cdot - 4$

Rewrite the expression.

$x = 6 \cdot - 4$

Simplify the right side.

Multiply $6$ by $- 4$ .

$x = - 24$

Solve for x 2/3(1/2x+12)=1/2(1/3x+14)-3 ?

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