Solve for x 2(3)-2(4x)+7=0

$2 (3) - 2 (4 x) + 7 = 0$

Step 1

Simplify $2 (3) - 2 \cdot (4 x) + 7$ .

Simplify each term.

Multiply $2$ by $3$ .

$6 - 2 \cdot (4 x) + 7 = 0$

Multiply $4$ by $- 2$ .

$6 - 8 x + 7 = 0$

Add $6$ and $7$ .

$- 8 x + 13 = 0$

Step 2

Subtract $13$ from both sides of the equation.

$- 8 x = - 13$

Step 3

Divide each term in $- 8 x = - 13$ by $- 8$ and simplify.

Divide each term in $- 8 x = - 13$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{- 13}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{- 13}{- 8}$

Divide $x$ by $1$ .

$x = \frac{- 13}{- 8}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{13}{8}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{13}{8}$

Decimal Form:

$x = 1.625$

Mixed Number Form:

$x = 1 \frac{5}{8}$