Solve for x 2+3/4(12x+4)=12x+4

$2 + \frac{3}{4} (12 x + 4) = 12 x + 4$

Step 1

Simplify $2 + \frac{3}{4} \cdot (12 x + 4)$ .

Simplify each term.

Apply the distributive property.

$2 + \frac{3}{4} (12 x) + \frac{3}{4} \cdot 4 = 12 x + 4$

Cancel the common factor of $4$ .

Factor $4$ out of $12 x$ .

$2 + \frac{3}{4} (4 (3 x)) + \frac{3}{4} \cdot 4 = 12 x + 4$

Cancel the common factor.

$2 + \frac{3}{4} (4 (3 x)) + \frac{3}{4} \cdot 4 = 12 x + 4$

Rewrite the expression.

$2 + 3 (3 x) + \frac{3}{4} \cdot 4 = 12 x + 4$

Multiply $3$ by $3$ .

$2 + 9 x + \frac{3}{4} \cdot 4 = 12 x + 4$

Cancel the common factor of $4$ .

Cancel the common factor.

$2 + 9 x + \frac{3}{4} \cdot 4 = 12 x + 4$

Rewrite the expression.

$2 + 9 x + 3 = 12 x + 4$

Add $2$ and $3$ .

$9 x + 5 = 12 x + 4$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $12 x$ from both sides of the equation.

$9 x + 5 - 12 x = 4$

Subtract $12 x$ from $9 x$ .

$- 3 x + 5 = 4$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 3 x = 4 - 5$

Subtract $5$ from $4$ .

$- 3 x = - 1$

Step 4

Divide each term in $- 3 x = - 1$ by $- 3$ and simplify.

Divide each term in $- 3 x = - 1$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 1}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 1}{- 3}$

Divide $x$ by $1$ .

$x = \frac{- 1}{- 3}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{1}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{3}$

Decimal Form:

$x = 0.\overline{3}$

Solve for x 2+3/4(12x+4)=12x+4

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