Solve for x (2/3)^(5x+1)=(27/8)^(x-4)

${(\frac{2}{3})}^{5 x + 1} = {(\frac{27}{8})}^{x - 4}$

Take the log of both sides of the equation.

$\ln ({(\frac{2}{3})}^{5 x + 1}) = \ln ({(\frac{27}{8})}^{x - 4})$

Expand $\ln ({(\frac{2}{3})}^{5 x + 1})$ by moving $5 x + 1$ outside the logarithm.

$(5 x + 1) \ln (\frac{2}{3}) = \ln ({(\frac{27}{8})}^{x - 4})$

Rewrite $\ln (\frac{2}{3})$ as $\ln (2) - \ln (3)$ .

$(5 x + 1) (\ln (2) - \ln (3)) = \ln ({(\frac{27}{8})}^{x - 4})$

Expand $\ln ({(\frac{27}{8})}^{x - 4})$ by moving $x - 4$ outside the logarithm.

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) \ln (\frac{27}{8})$

Rewrite $\ln (\frac{27}{8})$ as $\ln (27) - \ln (8)$ .

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - \ln (8))$

Rewrite $\ln (8)$ as $\ln (2^{3})$ .

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - \ln (2^{3}))$

Expand $\ln (2^{3})$ by moving $3$ outside the logarithm.

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - (3 \ln (2)))$

Multiply $3$ by $- 1$ .

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Solve the equation for $x$ .

Simplify $(5 x + 1) (\ln (2) - \ln (3))$ .

Start simplifying.

$0 + 0 + (5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Simplify by adding zeros.

$(5 x + 1) (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Expand $(5 x + 1) (\ln (2) - \ln (3))$ using the FOIL Method.

Apply the distributive property.

$5 x (\ln (2) - \ln (3)) + 1 (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Apply the distributive property.

$5 x \ln (2) + 5 x (- \ln (3)) + 1 (\ln (2) - \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Apply the distributive property.

$5 x \ln (2) + 5 x (- \ln (3)) + 1 \ln (2) + 1 (- \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Simplify each term.

Rewrite using the commutative property of multiplication.

$5 x \ln (2) + 5 \cdot - 1 x \ln (3) + 1 \ln (2) + 1 (- \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Multiply $5$ by $- 1$ .

$5 x \ln (2) - 5 x \ln (3) + 1 \ln (2) + 1 (- \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Multiply $\ln (2)$ by $1$ .

$5 x \ln (2) - 5 x \ln (3) + \ln (2) + 1 (- \ln (3)) = (x - 4) (\ln (27) - 3 \ln (2))$

Multiply $- \ln (3)$ by $1$ .

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = (x - 4) (\ln (27) - 3 \ln (2))$

Simplify $(x - 4) (\ln (27) - 3 \ln (2))$ .

Expand $(x - 4) (\ln (27) - 3 \ln (2))$ using the FOIL Method.

Apply the distributive property.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = x (\ln (27) - 3 \ln (2)) - 4 (\ln (27) - 3 \ln (2))$

Apply the distributive property.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = x \ln (27) + x (- 3 \ln (2)) - 4 (\ln (27) - 3 \ln (2))$

Apply the distributive property.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = x \ln (27) + x (- 3 \ln (2)) - 4 \ln (27) - 4 (- 3 \ln (2))$

Simplify each term.

Rewrite using the commutative property of multiplication.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = x \ln (27) - 3 x \ln (2) - 4 \ln (27) - 4 (- 3 \ln (2))$

Multiply $- 3$ by $- 4$ .

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) = x \ln (27) - 3 x \ln (2) - 4 \ln (27) + 12 \ln (2)$

Move all terms containing $x$ to the left side of the equation.

Subtract $x \ln (27)$ from both sides of the equation.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) - x \ln (27) = - 3 x \ln (2) - 4 \ln (27) + 12 \ln (2)$

Add $3 x \ln (2)$ to both sides of the equation.

$5 x \ln (2) - 5 x \ln (3) + \ln (2) - \ln (3) - x \ln (27) + 3 x \ln (2) = - 4 \ln (27) + 12 \ln (2)$

Add $5 x \ln (2)$ and $3 x \ln (2)$ .

$- 5 x \ln (3) + \ln (2) - \ln (3) - x \ln (27) + 8 x \ln (2) = - 4 \ln (27) + 12 \ln (2)$

Move all terms not containing $x$ to the right side of the equation.

Subtract $\ln (2)$ from both sides of the equation.

$- 5 x \ln (3) - \ln (3) - x \ln (27) + 8 x \ln (2) = - 4 \ln (27) + 12 \ln (2) - \ln (2)$

Add $\ln (3)$ to both sides of the equation.

$- 5 x \ln (3) - x \ln (27) + 8 x \ln (2) = - 4 \ln (27) + 12 \ln (2) - \ln (2) + \ln (3)$

Subtract $\ln (2)$ from $12 \ln (2)$ .

$- 5 x \ln (3) - x \ln (27) + 8 x \ln (2) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Factor $x$ out of $- 5 x \ln (3) - x \ln (27) + 8 x \ln (2)$ .

Factor $x$ out of $- 5 x \ln (3)$ .

$x (- 5 \ln (3)) - x \ln (27) + 8 x \ln (2) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Factor $x$ out of $- x \ln (27)$ .

$x (- 5 \ln (3)) + x (- 1 \ln (27)) + 8 x \ln (2) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Factor $x$ out of $8 x \ln (2)$ .

$x (- 5 \ln (3)) + x (- 1 \ln (27)) + x (8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Factor $x$ out of $x (- 5 \ln (3)) + x (- 1 \ln (27))$ .

$x (- 5 \ln (3) - 1 \ln (27)) + x (8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Factor $x$ out of $x (- 5 \ln (3) - 1 \ln (27)) + x (8 \ln (2))$ .

$x (- 5 \ln (3) - 1 \ln (27) + 8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Rewrite $- 1 \ln (27)$ as $- \ln (27)$ .

$x (- 5 \ln (3) - \ln (27) + 8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$

Divide each term in $x (- 5 \ln (3) - \ln (27) + 8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$ by $- 5 \ln (3) - \ln (27) + 8 \ln (2)$ and simplify.

Divide each term in $x (- 5 \ln (3) - \ln (27) + 8 \ln (2)) = - 4 \ln (27) + 11 \ln (2) + \ln (3)$ by $- 5 \ln (3) - \ln (27) + 8 \ln (2)$ .

$\frac{x (- 5 \ln (3) - \ln (27) + 8 \ln (2))}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} = \frac{- 4 \ln (27)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{11 \ln (2)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{\ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Simplify the left side.

Cancel the common factor of $- 5 \ln (3) - \ln (27) + 8 \ln (2)$ .

Cancel the common factor.

Divide $x$ by $1$ .

$x = \frac{- 4 \ln (27)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{11 \ln (2)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{\ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{4 \ln (27)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{11 \ln (2)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{\ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Simplify terms.

Combine the numerators over the common denominator.

$x = \frac{- 4 \ln (27) + 11 \ln (2)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)} + \frac{\ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Combine the numerators over the common denominator.

$x = \frac{- 4 \ln (27) + 11 \ln (2) + \ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- 4 \ln (27)$ .

$x = \frac{- (4 \ln (27)) + 11 \ln (2) + \ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $11 \ln (2)$ .

$x = \frac{- (4 \ln (27)) - (- 11 \ln (2)) + \ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- (4 \ln (27)) - (- 11 \ln (2))$ .

$x = \frac{- (4 \ln (27) - 11 \ln (2)) + \ln (3)}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $\ln (3)$ .

$x = \frac{- (4 \ln (27) - 11 \ln (2)) - 1 (- \ln (3))}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- (4 \ln (27) - 11 \ln (2)) - 1 (- \ln (3))$ .

$x = \frac{- (4 \ln (27) - 11 \ln (2) - \ln (3))}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Rewrite $- (4 \ln (27) - 11 \ln (2) - \ln (3))$ as $- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- 5 \ln (3) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- 5 \ln (3)$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- (5 \ln (3)) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- \ln (27)$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- (5 \ln (3)) - \ln (27) + 8 \ln (2)}$

Factor $- 1$ out of $- (5 \ln (3)) - \ln (27)$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- (5 \ln (3) + \ln (27)) + 8 \ln (2)}$

Factor $- 1$ out of $8 \ln (2)$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- (5 \ln (3) + \ln (27)) - (- 8 \ln (2))}$

Factor $- 1$ out of $- (5 \ln (3) + \ln (27)) - (- 8 \ln (2))$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- (5 \ln (3) + \ln (27) - 8 \ln (2))}$

Rewrite $- (5 \ln (3) + \ln (27) - 8 \ln (2))$ as $- 1 (5 \ln (3) + \ln (27) - 8 \ln (2))$ .

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- 1 (5 \ln (3) + \ln (27) - 8 \ln (2))}$

Cancel the common factor.

$x = \frac{- 1 (4 \ln (27) - 11 \ln (2) - \ln (3))}{- 1 (5 \ln (3) + \ln (27) - 8 \ln (2))}$

Rewrite the expression.

$x = \frac{4 \ln (27) - 11 \ln (2) - \ln (3)}{5 \ln (3) + \ln (27) - 8 \ln (2)}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{4 \ln (27) - 11 \ln (2) - \ln (3)}{5 \ln (3) + \ln (27) - 8 \ln (2)}$

Decimal Form:

$x = 1.375$

Solve for x (2/3)^(5x+1)=(27/8)^(x-4)

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