Solve for x 2/3(x-18y)=6y

$\frac{2}{3} (x - 18 y) = 6 y$

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} (\frac{2}{3} \cdot (x - 18 y)) = \frac{3}{2} (6 y)$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{2} (\frac{2}{3} \cdot (x - 18 y))$ .

Apply the distributive property.

$\frac{3}{2} (\frac{2}{3} x + \frac{2}{3} (- 18 y)) = \frac{3}{2} (6 y)$

Combine $\frac{2}{3}$ and $x$ .

$\frac{3}{2} (\frac{2 x}{3} + \frac{2}{3} (- 18 y)) = \frac{3}{2} (6 y)$

Cancel the common factor of $3$ .

Factor $3$ out of $- 18 y$ .

$\frac{3}{2} (\frac{2 x}{3} + \frac{2}{3} (3 (- 6 y))) = \frac{3}{2} (6 y)$

Cancel the common factor.

$\frac{3}{2} (\frac{2 x}{3} + \frac{2}{3} (3 (- 6 y))) = \frac{3}{2} (6 y)$

Rewrite the expression.

$\frac{3}{2} (\frac{2 x}{3} + 2 (- 6 y)) = \frac{3}{2} (6 y)$

Multiply $- 6$ by $2$ .

$\frac{3}{2} (\frac{2 x}{3} - 12 y) = \frac{3}{2} (6 y)$

Apply the distributive property.

$\frac{3}{2} \cdot \frac{2 x}{3} + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 x}{3} + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Rewrite the expression.

$\frac{1}{2} (2 x) + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$\frac{1}{2} (2 (x)) + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Cancel the common factor.

$\frac{1}{2} (2 x) + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Rewrite the expression.

$x + \frac{3}{2} (- 12 y) = \frac{3}{2} (6 y)$

Cancel the common factor of $2$ .

Factor $2$ out of $- 12 y$ .

$x + \frac{3}{2} (2 (- 6 y)) = \frac{3}{2} (6 y)$

Cancel the common factor.

$x + \frac{3}{2} (2 (- 6 y)) = \frac{3}{2} (6 y)$

Rewrite the expression.

$x + 3 (- 6 y) = \frac{3}{2} (6 y)$

Multiply $- 6$ by $3$ .

$x - 18 y = \frac{3}{2} (6 y)$

Simplify the right side.

Simplify $\frac{3}{2} (6 y)$ .

Cancel the common factor of $2$ .

Factor $2$ out of $6 y$ .

$x - 18 y = \frac{3}{2} (2 (3 y))$

Cancel the common factor.

$x - 18 y = \frac{3}{2} (2 (3 y))$

Rewrite the expression.

$x - 18 y = 3 (3 y)$

Multiply $3$ by $3$ .

$x - 18 y = 9 y$

Move all terms not containing $x$ to the right side of the equation.

Add $18 y$ to both sides of the equation.

$x = 9 y + 18 y$

Add $9 y$ and $18 y$ .

$x = 27 y$

Solve for x 2/3(x-18y)=6y

Related Questions

Support LCMGCF.com by disabling your adblocker.