Solve for x (2-3i)+(x+yi)=6

$(2 - 3 i) + (x + y i) = 6$

Step 1

Subtract $2$ from both sides of the equation.

$- 3 i + x + y i = 6 - 2$

Step 2

Add $3 i$ to both sides of the equation.

$x + y i = 6 - 2 + 3 i$

Step 3

Subtract $y i$ from both sides of the equation.

$x = 6 - 2 + 3 i - y i$

Step 4

Subtract $2$ from $6$ .

$x = 4 + 3 i - y i$

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