Solve for x -2(3x-1)+x=14-x

$- 2 (3 x - 1) + x = 14 - x$

Step 1

Simplify $- 2 (3 x - 1) + x$ .

Simplify each term.

Apply the distributive property.

$- 2 (3 x) - 2 \cdot - 1 + x = 14 - x$

Multiply $3$ by $- 2$ .

$- 6 x - 2 \cdot - 1 + x = 14 - x$

Multiply $- 2$ by $- 1$ .

$- 6 x + 2 + x = 14 - x$

Add $- 6 x$ and $x$ .

$- 5 x + 2 = 14 - x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$- 5 x + 2 + x = 14$

Add $- 5 x$ and $x$ .

$- 4 x + 2 = 14$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$- 4 x = 14 - 2$

Subtract $2$ from $14$ .

$- 4 x = 12$

Step 4

Divide each term in $- 4 x = 12$ by $- 4$ and simplify.

Divide each term in $- 4 x = 12$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{12}{- 4}$

Divide $x$ by $1$ .

$x = \frac{12}{- 4}$

Simplify the right side.

Divide $12$ by $- 4$ .

$x = - 3$