Solve for x -2(3x-10)+8x=7x+20+7x

$- 2 (3 x - 10) + 8 x = 7 x + 20 + 7 x$

Simplify $- 2 (3 x - 10) + 8 x$ .

Simplify each term.

Apply the distributive property.

$- 2 (3 x) - 2 \cdot - 10 + 8 x = 7 x + 20 + 7 x$

Multiply $3$ by $- 2$ .

$- 6 x - 2 \cdot - 10 + 8 x = 7 x + 20 + 7 x$

Multiply $- 2$ by $- 10$ .

$- 6 x + 20 + 8 x = 7 x + 20 + 7 x$

Add $- 6 x$ and $8 x$ .

$2 x + 20 = 7 x + 20 + 7 x$

Add $7 x$ and $7 x$ .

$2 x + 20 = 14 x + 20$

Move all terms containing $x$ to the left side of the equation.

Subtract $14 x$ from both sides of the equation.

$2 x + 20 - 14 x = 20$

Subtract $14 x$ from $2 x$ .

$- 12 x + 20 = 20$

Move all terms not containing $x$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$- 12 x = 20 - 20$

Subtract $20$ from $20$ .

$- 12 x = 0$

Divide each term in $- 12 x = 0$ by $- 12$ and simplify.

Divide each term in $- 12 x = 0$ by $- 12$ .

$\frac{- 12 x}{- 12} = \frac{0}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 x}{- 12} = \frac{0}{- 12}$

Divide $x$ by $1$ .

$x = \frac{0}{- 12}$

Simplify the right side.

Divide $0$ by $- 12$ .

$x = 0$