Solve for x 2/3x^3+x^2-5x=-9

$\frac{2}{3} x^{3} + x^{2} - 5 x = - 9$

Combine $\frac{2}{3}$ and $x^{3}$ .

$\frac{2 x^{3}}{3} + x^{2} - 5 x = - 9$

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx - 4.11765034$