Solve for x 2(3x-4)=4(1/2x-8)

$2 (3 x - 4) = 4 (\frac{1}{2} x - 8)$

Simplify $2 (3 x - 4)$ .

Start simplifying.

$0 + 0 + 2 (3 x - 4) = 4 (\frac{1}{2} x - 8)$

Simplify by adding zeros.

$2 (3 x - 4) = 4 (\frac{1}{2} x - 8)$

Apply the distributive property.

$2 (3 x) + 2 \cdot - 4 = 4 (\frac{1}{2} x - 8)$

Multiply.

Multiply $3$ by $2$ .

$6 x + 2 \cdot - 4 = 4 (\frac{1}{2} x - 8)$

Multiply $2$ by $- 4$ .

$6 x - 8 = 4 (\frac{1}{2} x - 8)$

Simplify $4 (\frac{1}{2} x - 8)$ .

Combine $\frac{1}{2}$ and $x$ .

$6 x - 8 = 4 (\frac{x}{2} - 8)$

Apply the distributive property.

$6 x - 8 = 4 \frac{x}{2} + 4 \cdot - 8$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$6 x - 8 = 2 (2) \frac{x}{2} + 4 \cdot - 8$

Cancel the common factor.

$6 x - 8 = 2 \cdot 2 \frac{x}{2} + 4 \cdot - 8$

Rewrite the expression.

$6 x - 8 = 2 x + 4 \cdot - 8$

Multiply $4$ by $- 8$ .

$6 x - 8 = 2 x - 32$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$6 x - 8 - 2 x = - 32$

Subtract $2 x$ from $6 x$ .

$4 x - 8 = - 32$

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$4 x = - 32 + 8$

Add $- 32$ and $8$ .

$4 x = - 24$

Divide each term in $4 x = - 24$ by $4$ and simplify.

Divide each term in $4 x = - 24$ by $4$ .

$\frac{4 x}{4} = \frac{- 24}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 24}{4}$

Divide $x$ by $1$ .

$x = \frac{- 24}{4}$

Simplify the right side.

Divide $- 24$ by $4$ .

$x = - 6$

Solve for x 2(3x-4)=4(1/2x-8)

Related Questions

Support LCMGCF.com by disabling your adblocker.