Solve for x 2(3x+4)=5x+3x-4

$2 (3 x + 4) = 5 x + 3 x - 4$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$5 x + 3 x - 4 = 2 (3 x + 4)$

Step 2

Add $5 x$ and $3 x$ .

$8 x - 4 = 2 (3 x + 4)$

Step 3

Simplify $2 (3 x + 4)$ .

Apply the distributive property.

$8 x - 4 = 2 (3 x) + 2 \cdot 4$

Multiply.

Multiply $3$ by $2$ .

$8 x - 4 = 6 x + 2 \cdot 4$

Multiply $2$ by $4$ .

$8 x - 4 = 6 x + 8$

Step 4

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$8 x - 4 - 6 x = 8$

Subtract $6 x$ from $8 x$ .

$2 x - 4 = 8$

Step 5

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$2 x = 8 + 4$

Add $8$ and $4$ .

$2 x = 12$

Step 6

Divide each term in $2 x = 12$ by $2$ and simplify.

Divide each term in $2 x = 12$ by $2$ .

$\frac{2 x}{2} = \frac{12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{12}{2}$

Divide $x$ by $1$ .

$x = \frac{12}{2}$

Simplify the right side.

Divide $12$ by $2$ .

$x = 6$