Solve for x 2(3x-4)=x+2

$2 (3 x - 4) = x + 2$

Step 1

Simplify $2 (3 x - 4)$ .

Rewrite.

$0 + 0 + 2 (3 x - 4) = x + 2$

Simplify by adding zeros.

$2 (3 x - 4) = x + 2$

Apply the distributive property.

$2 (3 x) + 2 \cdot - 4 = x + 2$

Multiply.

Multiply $3$ by $2$ .

$6 x + 2 \cdot - 4 = x + 2$

Multiply $2$ by $- 4$ .

$6 x - 8 = x + 2$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$6 x - 8 - x = 2$

Subtract $x$ from $6 x$ .

$5 x - 8 = 2$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$5 x = 2 + 8$

Add $2$ and $8$ .

$5 x = 10$

Step 4

Divide each term in $5 x = 10$ by $5$ and simplify.

Divide each term in $5 x = 10$ by $5$ .

$\frac{5 x}{5} = \frac{10}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{10}{5}$

Divide $x$ by $1$ .

$x = \frac{10}{5}$

Simplify the right side.

Divide $10$ by $5$ .

$x = 2$