Solve for x 2(3x+5)=22

$2 (3 x + 5) = 22$

Step 1

Divide each term in $2 (3 x + 5) = 22$ by $2$ and simplify.

Divide each term in $2 (3 x + 5) = 22$ by $2$ .

$\frac{2 (3 x + 5)}{2} = \frac{22}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (3 x + 5)}{2} = \frac{22}{2}$

Divide $3 x + 5$ by $1$ .

$3 x + 5 = \frac{22}{2}$

Simplify the right side.

Divide $22$ by $2$ .

$3 x + 5 = 11$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$3 x = 11 - 5$

Subtract $5$ from $11$ .

$3 x = 6$

Step 3

Divide each term in $3 x = 6$ by $3$ and simplify.

Divide each term in $3 x = 6$ by $3$ .

$\frac{3 x}{3} = \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{6}{3}$

Divide $x$ by $1$ .

$x = \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$