Solve for x 2(3x+8)=2x+16+4x

$2 (3 x + 8) = 2 x + 16 + 4 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 x + 16 + 4 x = 2 (3 x + 8)$

Add $2 x$ and $4 x$ .

$6 x + 16 = 2 (3 x + 8)$

Simplify $2 (3 x + 8)$ .

Apply the distributive property.

$6 x + 16 = 2 (3 x) + 2 \cdot 8$

Multiply.

Multiply $3$ by $2$ .

$6 x + 16 = 6 x + 2 \cdot 8$

Multiply $2$ by $8$ .

$6 x + 16 = 6 x + 16$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x + 16 - 6 x = 16$

Combine the opposite terms in $6 x + 16 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 + 16 = 16$

Add $0$ and $16$ .

$16 = 16$

Since $16 = 16$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$