Solve for x 2=(4^(1/3))(2^(x/3))

$2 = (4^{\frac{1}{3}}) (2^{\frac{x}{3}})$

Rewrite the equation as $4^{\frac{1}{3}} \cdot 2^{\frac{x}{3}} = 2$ .

$4^{\frac{1}{3}} \cdot 2^{\frac{x}{3}} = 2$

Rewrite $4$ as $2^{2}$ .

${(2^{2})}^{\frac{1}{3}} \cdot 2^{\frac{x}{3}} = 2$

Multiply the exponents in ${(2^{2})}^{\frac{1}{3}}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$2^{2 (\frac{1}{3})} \cdot 2^{\frac{x}{3}} = 2$

Combine $2$ and $\frac{1}{3}$ .

$2^{\frac{2}{3}} \cdot 2^{\frac{x}{3}} = 2$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2^{\frac{2}{3} + \frac{x}{3}} = 2$

Create equivalent expressions in the equation that all have equal bases.

$2^{\frac{2}{3} + \frac{x}{3}} = 2^{1}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$\frac{2}{3} + \frac{x}{3} = 1$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $\frac{2}{3}$ from both sides of the equation.

$\frac{x}{3} = 1 - \frac{2}{3}$

Write $1$ as a fraction with a common denominator.

$\frac{x}{3} = \frac{3}{3} - \frac{2}{3}$

Combine the numerators over the common denominator.

$\frac{x}{3} = \frac{3 - 2}{3}$

Subtract $2$ from $3$ .

$\frac{x}{3} = \frac{1}{3}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$x = 1$