Solve for x -2(4-x)+x>-25

$- 2 (4 - x) + x > - 25$

Step 1

Simplify $- 2 (4 - x) + x$ .

Simplify each term.

Apply the distributive property.

$- 2 \cdot 4 - 2 (- x) + x > - 25$

Multiply $- 2$ by $4$ .

$- 8 - 2 (- x) + x > - 25$

Multiply $- 1$ by $- 2$ .

$- 8 + 2 x + x > - 25$

Add $2 x$ and $x$ .

$- 8 + 3 x > - 25$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$3 x > - 25 + 8$

Add $- 25$ and $8$ .

$3 x > - 17$

Step 3

Divide each term in $3 x > - 17$ by $3$ and simplify.

Divide each term in $3 x > - 17$ by $3$ .

$\frac{3 x}{3} > \frac{- 17}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} > \frac{- 17}{3}$

Divide $x$ by $1$ .

$x > \frac{- 17}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$x > - \frac{17}{3}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > - \frac{17}{3}$

Interval Notation:

$(- \frac{17}{3}, \infty)$