Solve for x 2/5*(10x-3)-x=9/5

$\frac{2}{5} \cdot (10 x - 3) - x = \frac{9}{5}$

Step 1

Simplify $\frac{2}{5} \cdot (10 x - 3) - x$ .

Simplify each term.

Apply the distributive property.

$\frac{2}{5} (10 x) + \frac{2}{5} \cdot - 3 - x = \frac{9}{5}$

Cancel the common factor of $5$ .

Factor $5$ out of $10 x$ .

$\frac{2}{5} (5 (2 x)) + \frac{2}{5} \cdot - 3 - x = \frac{9}{5}$

Cancel the common factor.

$\frac{2}{5} (5 (2 x)) + \frac{2}{5} \cdot - 3 - x = \frac{9}{5}$

Rewrite the expression.

$2 (2 x) + \frac{2}{5} \cdot - 3 - x = \frac{9}{5}$

Multiply $2$ by $2$ .

$4 x + \frac{2}{5} \cdot - 3 - x = \frac{9}{5}$

Multiply $\frac{2}{5} \cdot - 3$ .

Combine $\frac{2}{5}$ and $- 3$ .

$4 x + \frac{2 \cdot - 3}{5} - x = \frac{9}{5}$

Multiply $2$ by $- 3$ .

$4 x + \frac{- 6}{5} - x = \frac{9}{5}$

Move the negative in front of the fraction.

$4 x - \frac{6}{5} - x = \frac{9}{5}$

Subtract $x$ from $4 x$ .

$3 x - \frac{6}{5} = \frac{9}{5}$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $\frac{6}{5}$ to both sides of the equation.

$3 x = \frac{9}{5} + \frac{6}{5}$

Combine the numerators over the common denominator.

$3 x = \frac{9 + 6}{5}$

Add $9$ and $6$ .

$3 x = \frac{15}{5}$

Divide $15$ by $5$ .

$3 x = 3$

Step 3

Divide each term in $3 x = 3$ by $3$ and simplify.

Divide each term in $3 x = 3$ by $3$ .

$\frac{3 x}{3} = \frac{3}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{3}{3}$

Divide $x$ by $1$ .

$x = \frac{3}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$x = 1$

Solve for x 2/5*(10x-3)-x=9/5

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