Solve for x 2/5*(x+1)=g

$\frac{2}{5} \cdot (x + 1) = g$

Step 1

Multiply both sides of the equation by $\frac{5}{2}$ .

$\frac{5}{2} (\frac{2}{5} \cdot (x + 1)) = \frac{5}{2} g$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{2} (\frac{2}{5} \cdot (x + 1))$ .

Apply the distributive property.

$\frac{5}{2} (\frac{2}{5} x + \frac{2}{5} \cdot 1) = \frac{5}{2} g$

Combine $\frac{2}{5}$ and $x$ .

$\frac{5}{2} (\frac{2 x}{5} + \frac{2}{5} \cdot 1) = \frac{5}{2} g$

Multiply $\frac{2}{5}$ by $1$ .

$\frac{5}{2} (\frac{2 x}{5} + \frac{2}{5}) = \frac{5}{2} g$

Apply the distributive property.

$\frac{5}{2} \cdot \frac{2 x}{5} + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{2} \cdot \frac{2 x}{5} + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Rewrite the expression.

$\frac{1}{2} (2 x) + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$\frac{1}{2} (2 (x)) + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Cancel the common factor.

$\frac{1}{2} (2 x) + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Rewrite the expression.

$x + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Cancel the common factor of $5$ .

Cancel the common factor.

$x + \frac{5}{2} \cdot \frac{2}{5} = \frac{5}{2} g$

Rewrite the expression.

$x + \frac{1}{2} \cdot 2 = \frac{5}{2} g$

Cancel the common factor of $2$ .

Cancel the common factor.

$x + \frac{1}{2} \cdot 2 = \frac{5}{2} g$

Rewrite the expression.

$x + 1 = \frac{5}{2} g$

Simplify the right side.

Combine $\frac{5}{2}$ and $g$ .

$x + 1 = \frac{5 g}{2}$

Step 3

Subtract $1$ from both sides of the equation.

$x = \frac{5 g}{2} - 1$