Solve for x -2/5(x-10)=3(x+2)

$- \frac{2}{5} (x - 10) = 3 (x + 2)$

Simplify $- \frac{2}{5} \cdot (x - 10)$ .

Start simplifying.

$0 + 0 - \frac{2}{5} \cdot (x - 10) = 3 (x + 2)$

Simplify terms.

Apply the distributive property.

$- \frac{2}{5} x - \frac{2}{5} \cdot - 10 = 3 (x + 2)$

Combine $x$ and $\frac{2}{5}$ .

$- \frac{x \cdot 2}{5} - \frac{2}{5} \cdot - 10 = 3 (x + 2)$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{2}{5}$ into the numerator.

$- \frac{x \cdot 2}{5} + \frac{- 2}{5} \cdot - 10 = 3 (x + 2)$

Factor $5$ out of $- 10$ .

$- \frac{x \cdot 2}{5} + \frac{- 2}{5} \cdot (5 (- 2)) = 3 (x + 2)$

Cancel the common factor.

$- \frac{x \cdot 2}{5} + \frac{- 2}{5} \cdot (5 \cdot - 2) = 3 (x + 2)$

Rewrite the expression.

$- \frac{x \cdot 2}{5} - 2 \cdot - 2 = 3 (x + 2)$

Multiply $- 2$ by $- 2$ .

$- \frac{x \cdot 2}{5} + 4 = 3 (x + 2)$

Move $2$ to the left of $x$ .

$- \frac{2 x}{5} + 4 = 3 (x + 2)$

Simplify $3 (x + 2)$ .

Apply the distributive property.

$- \frac{2 x}{5} + 4 = 3 x + 3 \cdot 2$

Multiply $3$ by $2$ .

$- \frac{2 x}{5} + 4 = 3 x + 6$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$- \frac{2 x}{5} + 4 - 3 x = 6$

To write $- 3 x$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{2 x}{5} - 3 x \cdot \frac{5}{5} + 4 = 6$

Combine $- 3 x$ and $\frac{5}{5}$ .

$- \frac{2 x}{5} + \frac{- 3 x \cdot 5}{5} + 4 = 6$

Combine the numerators over the common denominator.

$\frac{- 2 x - 3 x \cdot 5}{5} + 4 = 6$

Simplify each term.

Simplify the numerator.

Factor $x$ out of $- 2 x - 3 x \cdot 5$ .

Factor $x$ out of $- 2 x$ .

$\frac{x \cdot - 2 - 3 x \cdot 5}{5} + 4 = 6$

Factor $x$ out of $- 3 x \cdot 5$ .

$\frac{x \cdot - 2 + x (- 3 \cdot 5)}{5} + 4 = 6$

Factor $x$ out of $x \cdot - 2 + x (- 3 \cdot 5)$ .

$\frac{x (- 2 - 3 \cdot 5)}{5} + 4 = 6$

Multiply $- 3$ by $5$ .

$\frac{x (- 2 - 15)}{5} + 4 = 6$

Subtract $15$ from $- 2$ .

$\frac{x \cdot - 17}{5} + 4 = 6$

Move $- 17$ to the left of $x$ .

$\frac{- 17 \cdot x}{5} + 4 = 6$

Move the negative in front of the fraction.

$- \frac{17 x}{5} + 4 = 6$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- \frac{17 x}{5} = 6 - 4$

Subtract $4$ from $6$ .

$- \frac{17 x}{5} = 2$

Multiply both sides of the equation by $- \frac{5}{17}$ .

$- \frac{5}{17} (- \frac{17 x}{5}) = - \frac{5}{17} \cdot 2$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{5}{17} (- \frac{17 x}{5})$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{17}$ into the numerator.

$\frac{- 5}{17} (- \frac{17 x}{5}) = - \frac{5}{17} \cdot 2$

Move the leading negative in $- \frac{17 x}{5}$ into the numerator.

$\frac{- 5}{17} \cdot \frac{- 17 x}{5} = - \frac{5}{17} \cdot 2$

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{17} \cdot \frac{- 17 x}{5} = - \frac{5}{17} \cdot 2$

Cancel the common factor.

$\frac{5 \cdot - 1}{17} \cdot \frac{- 17 x}{5} = - \frac{5}{17} \cdot 2$

Rewrite the expression.

$\frac{- 1}{17} (- 17 x) = - \frac{5}{17} \cdot 2$

Cancel the common factor of $17$ .

Factor $17$ out of $- 17 x$ .

$\frac{- 1}{17} (17 (- x)) = - \frac{5}{17} \cdot 2$

Cancel the common factor.

$\frac{- 1}{17} (17 (- x)) = - \frac{5}{17} \cdot 2$

Rewrite the expression.

$- - x = - \frac{5}{17} \cdot 2$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{5}{17} \cdot 2$

Multiply $x$ by $1$ .

$x = - \frac{5}{17} \cdot 2$

Simplify the right side.

Simplify $- \frac{5}{17} \cdot 2$ .

Multiply $- \frac{5}{17} \cdot 2$ .

Multiply $2$ by $- 1$ .

$x = - 2 (\frac{5}{17})$

Combine $- 2$ and $\frac{5}{17}$ .

$x = \frac{- 2 \cdot 5}{17}$

Multiply $- 2$ by $5$ .

$x = \frac{- 10}{17}$

Move the negative in front of the fraction.

$x = - \frac{10}{17}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{10}{17}$

Decimal Form:

$x = - 0.58823529 \dots$

Solve for x -2/5(x-10)=3(x+2)

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