Solve for x 2/5(x-2)=-3

$\frac{2}{5} (x - 2) = - 3$

Multiply both sides of the equation by $\frac{5}{2}$ .

$\frac{5}{2} (\frac{2}{5} \cdot (x - 2)) = \frac{5}{2} \cdot - 3$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{2} (\frac{2}{5} \cdot (x - 2))$ .

Apply the distributive property.

$\frac{5}{2} (\frac{2}{5} x + \frac{2}{5} \cdot - 2) = \frac{5}{2} \cdot - 3$

Combine $\frac{2}{5}$ and $x$ .

$\frac{5}{2} (\frac{2 x}{5} + \frac{2}{5} \cdot - 2) = \frac{5}{2} \cdot - 3$

Multiply $\frac{2}{5} \cdot - 2$ .

Combine $\frac{2}{5}$ and $- 2$ .

$\frac{5}{2} (\frac{2 x}{5} + \frac{2 \cdot - 2}{5}) = \frac{5}{2} \cdot - 3$

Multiply $2$ by $- 2$ .

$\frac{5}{2} (\frac{2 x}{5} + \frac{- 4}{5}) = \frac{5}{2} \cdot - 3$

Move the negative in front of the fraction.

$\frac{5}{2} (\frac{2 x}{5} - \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Apply the distributive property.

$\frac{5}{2} \cdot \frac{2 x}{5} + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{2} \cdot \frac{2 x}{5} + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Rewrite the expression.

$\frac{1}{2} (2 x) + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$\frac{1}{2} (2 (x)) + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Cancel the common factor.

$\frac{1}{2} (2 x) + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Rewrite the expression.

$x + \frac{5}{2} (- \frac{4}{5}) = \frac{5}{2} \cdot - 3$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{4}{5}$ into the numerator.

$x + \frac{5}{2} \cdot \frac{- 4}{5} = \frac{5}{2} \cdot - 3$

Cancel the common factor.

$x + \frac{5}{2} \cdot \frac{- 4}{5} = \frac{5}{2} \cdot - 3$

Rewrite the expression.

$x + \frac{1}{2} \cdot - 4 = \frac{5}{2} \cdot - 3$

Cancel the common factor of $2$ .

Factor $2$ out of $- 4$ .

$x + \frac{1}{2} \cdot (2 (- 2)) = \frac{5}{2} \cdot - 3$

Cancel the common factor.

$x + \frac{1}{2} \cdot (2 \cdot - 2) = \frac{5}{2} \cdot - 3$

Rewrite the expression.

$x - 2 = \frac{5}{2} \cdot - 3$

Simplify the right side.

Simplify $\frac{5}{2} \cdot - 3$ .

Multiply $\frac{5}{2} \cdot - 3$ .

Combine $\frac{5}{2}$ and $- 3$ .

$x - 2 = \frac{5 \cdot - 3}{2}$

Multiply $5$ by $- 3$ .

$x - 2 = \frac{- 15}{2}$

Move the negative in front of the fraction.

$x - 2 = - \frac{15}{2}$

Move all terms not containing $x$ to the right side of the equation.

Add $2$ to both sides of the equation.

$x = - \frac{15}{2} + 2$

To write $2$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = - \frac{15}{2} + 2 \cdot \frac{2}{2}$

Combine $2$ and $\frac{2}{2}$ .

$x = - \frac{15}{2} + \frac{2 \cdot 2}{2}$

Combine the numerators over the common denominator.

$x = \frac{- 15 + 2 \cdot 2}{2}$

Simplify the numerator.

Multiply $2$ by $2$ .

$x = \frac{- 15 + 4}{2}$

Add $- 15$ and $4$ .

$x = \frac{- 11}{2}$

Move the negative in front of the fraction.

$x = - \frac{11}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{11}{2}$

Decimal Form:

$x = - 5.5$

Mixed Number Form:

$x = - 5 \frac{1}{2}$

Solve for x 2/5(x-2)=-3

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