Solve for x 2-5(x+5)=3(x-2)-1

$2 - 5 (x + 5) = 3 (x - 2) - 1$

Simplify $2 - 5 (x + 5)$ .

Simplify each term.

Apply the distributive property.

$2 - 5 x - 5 \cdot 5 = 3 (x - 2) - 1$

Multiply $- 5$ by $5$ .

$2 - 5 x - 25 = 3 (x - 2) - 1$

Subtract $25$ from $2$ .

$- 5 x - 23 = 3 (x - 2) - 1$

Simplify $3 (x - 2) - 1$ .

Simplify each term.

Apply the distributive property.

$- 5 x - 23 = 3 x + 3 \cdot - 2 - 1$

Multiply $3$ by $- 2$ .

$- 5 x - 23 = 3 x - 6 - 1$

Subtract $1$ from $- 6$ .

$- 5 x - 23 = 3 x - 7$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$- 5 x - 23 - 3 x = - 7$

Subtract $3 x$ from $- 5 x$ .

$- 8 x - 23 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Add $23$ to both sides of the equation.

$- 8 x = - 7 + 23$

Add $- 7$ and $23$ .

$- 8 x = 16$

Divide each term in $- 8 x = 16$ by $- 8$ and simplify.

Divide each term in $- 8 x = 16$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{16}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{16}{- 8}$

Divide $x$ by $1$ .

$x = \frac{16}{- 8}$

Simplify the right side.

Divide $16$ by $- 8$ .

$x = - 2$