Solve for x 2(5x-20)-(15+8x)=7

$2 (5 x - 20) - (15 + 8 x) = 7$

Step 1

Simplify $2 (5 x - 20) - (15 + 8 x)$ .

Simplify each term.

Apply the distributive property.

$2 (5 x) + 2 \cdot - 20 - (15 + 8 x) = 7$

Multiply $5$ by $2$ .

$10 x + 2 \cdot - 20 - (15 + 8 x) = 7$

Multiply $2$ by $- 20$ .

$10 x - 40 - (15 + 8 x) = 7$

Apply the distributive property.

$10 x - 40 - 1 \cdot 15 - (8 x) = 7$

Multiply $- 1$ by $15$ .

$10 x - 40 - 15 - (8 x) = 7$

Multiply $8$ by $- 1$ .

$10 x - 40 - 15 - 8 x = 7$

Simplify by adding terms.

Subtract $8 x$ from $10 x$ .

$2 x - 40 - 15 = 7$

Subtract $15$ from $- 40$ .

$2 x - 55 = 7$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $55$ to both sides of the equation.

$2 x = 7 + 55$

Add $7$ and $55$ .

$2 x = 62$

Step 3

Divide each term in $2 x = 62$ by $2$ and simplify.

Divide each term in $2 x = 62$ by $2$ .

$\frac{2 x}{2} = \frac{62}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{62}{2}$

Divide $x$ by $1$ .

$x = \frac{62}{2}$

Simplify the right side.

Divide $62$ by $2$ .

$x = 31$