Solve for x 2(5x+8)=6x+20

$2 (5 x + 8) = 6 x + 20$

Step 1

Simplify $2 (5 x + 8)$ .

Rewrite.

$0 + 0 + 2 (5 x + 8) = 6 x + 20$

Simplify by adding zeros.

$2 (5 x + 8) = 6 x + 20$

Apply the distributive property.

$2 (5 x) + 2 \cdot 8 = 6 x + 20$

Multiply.

Multiply $5$ by $2$ .

$10 x + 2 \cdot 8 = 6 x + 20$

Multiply $2$ by $8$ .

$10 x + 16 = 6 x + 20$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$10 x + 16 - 6 x = 20$

Subtract $6 x$ from $10 x$ .

$4 x + 16 = 20$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $16$ from both sides of the equation.

$4 x = 20 - 16$

Subtract $16$ from $20$ .

$4 x = 4$

Step 4

Divide each term in $4 x = 4$ by $4$ and simplify.

Divide each term in $4 x = 4$ by $4$ .

$\frac{4 x}{4} = \frac{4}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{4}{4}$

Divide $x$ by $1$ .

$x = \frac{4}{4}$

Simplify the right side.

Divide $4$ by $4$ .

$x = 1$