Solve for x 2(6x+9-3x)=5x+21

$2 (6 x + 9 - 3 x) = 5 x + 21$

Simplify $2 (6 x + 9 - 3 x)$ .

Rewrite.

$0 + 0 + 2 (6 x + 9 - 3 x) = 5 x + 21$

Simplify by adding zeros.

$2 (6 x + 9 - 3 x) = 5 x + 21$

Subtract $3 x$ from $6 x$ .

$2 (3 x + 9) = 5 x + 21$

Apply the distributive property.

$2 (3 x) + 2 \cdot 9 = 5 x + 21$

Multiply.

Multiply $3$ by $2$ .

$6 x + 2 \cdot 9 = 5 x + 21$

Multiply $2$ by $9$ .

$6 x + 18 = 5 x + 21$

Move all terms containing $x$ to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$6 x + 18 - 5 x = 21$

Subtract $5 x$ from $6 x$ .

$x + 18 = 21$

Move all terms not containing $x$ to the right side of the equation.

Subtract $18$ from both sides of the equation.

$x = 21 - 18$

Subtract $18$ from $21$ .

$x = 3$